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TUESDAY, MARCH MA[[R]]CH 03, 2009

[[Silverlight ]] Multi-part File Upload Form Post

[[Silverlight ]] not actually very web friendly. It lacks of built-in support for the current HTML form post protocol. So, we have to write it our own. I have written an extension class and two serializer classes, one for normal form post (DataContractQueryStringSerializer) while the other for multipart upload form post (DataContractMultiPartSerializer).

public static void PostFormAsync(this HttpWebRequest HttpWeb[[R]]equest request, object parameters, AsyncCallback callback) { request.Method = "POST"; request.ContentType = "applicatio n/x-www-form-urlencoded"; request.BeginGetRequestStreamBeginGet[[R]]equestStream(new AsyncCallback(asyncResult async[[R]]esult => { Stream stream = request.EndGe tRequestStreamt[[R]]equestStream(asyncResultasync[[R]]esult); DataContractQueryStringSerial izer ser = new DataContractQueryStringSeria lizer(); ser.WriteObject(stream, param eters); stream.Close(); request.BeginGetResponseBeginGet[[R]]esponse(call back, request); }), request); }

public static void PostMultiPartAsync (this HttpWebRequest HttpWeb[[R]]equest request, object parame ters, AsyncCallback callback) { request.Method = "POST"; string boundary = "---------------" + DateTime.Now.Ticks.ToString(); request.ContentType = "multipart/form-data; boundary=" + boundary; request.BeginGetRequestStreamBeginGet[[R]]equestStream(new AsyncCallback(asyncResult async[[R]]esult => { Stream stream = request.EndGe tRequestStreamt[[R]]equestStream(asyncResultasync[[R]]esult);

DataContractMultiPartSerializ er ser = new DataContractMultiPartSerialize r(boundary); ser.WriteObject(stream, param eters); stream.Close(); request.BeginGetResponseBeginGet[[R]]esponse(call back, request); }), request); }

<blockquote>0}={1}&", member.Name ?? prop.Name, prop. GetValue(data)); } } } foreach (var prop in data .GetType().GetProperties()) { if (prop.CanReadCan[[R]]ead) { foreach (var attr ibute in prop.GetCustomAttributes(true)) {</blockquote>

FileInfo f = value as Fil eInfo; writer.WriteLine(@"Conten t-Disposition: form-data; name=""{0}""; fil ename=""{1}""", key, f.Name); writer.WriteLine("Content -Type: application/octet-stream"); writer.WriteLine("Content -Length: " + f.Length); writer.WriteLine(); writer.Flush(); Stream output = writer.Ba seStream; Stream input = f.OpenReadOpen[[R]]ead

iter, member.Name ?? prop.Name, prop.GetVal ue(data)); } } } foreach (var prop in data .GetType().GetProperties()) { if (prop.CanReadCan[[R]]ead) { foreach (var attr ibute in prop.GetCustomAttributes(true)) {

The usage is as follows: First a [[PHP ]] file

public Page() { InitializeComponent(); // Create a request object HttpWebRequest HttpWeb[[R]]equest request = (HttpWeb Request[[R]]equest)WebRequestWeb[[R]]equest.Create(new Uri("http://l ocalhost/rms/test.php")); OpenFileDialog dlg = new OpenFile Dialog(); if (dlg.ShowDialog().Value) { request.PostMultiPartAsync(ne w Dictionary<string, object> { { "x", "1" } , { "y", dlg.File } }, new AsyncCallback(as yncResult ync[[R]]esult => { HttpWebResponse HttpWeb[[R]]esponse response = (HttpWebResponseHttpWeb[[R]]esponse)request.EndGetResponseEndGet[[R]]esponse(a syncResultsync[[R]]esult);

Stream responseStream = r esponse.GetResponseStreamGet[[R]]esponseStream(); StreamReader Stream[[R]]eader reader = new StreamReaderStream[[R]]eader(responseStream); this.Dispatcher.BeginInvo ke(delegate { // output is a TextBl

output.Text = reader. ReadToEnd[[R]]eadToEnd(); response.Close(); }); })); } }

Hi, I failed in EndGetResponseEndGet[[R]]esponse(), and got security exception. What will the encoding data would like? Could you give me an example?

Could you post the receiving recei[[vi]]ng part? Meaning, how to take the multipart request in the server (Jersey) and process the multipart request?

standard Java Web Container (e.g. [[Tomcat]]) will be able to process it natively.

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